1. In an experimental plot of <i>Oryza sativa</i>, a researcher aims to produce exactly $600$ viable seeds. What is the minimum number of meiotic divisions required to achieve this?
A) $600$
B) $150$
C) $750$
D) $1200$
Correct Answer: C
To produce $n$ seeds: <br>1. $n$ pollen grains are needed. Since 1 meiosis $\rightarrow$ 4 pollen grains, we need $n/4$ divisions. <br>2. $n$ ovules (embryo sacs) are needed. Since 1 meiosis $\rightarrow$ 1 functional megaspore, we need $n$ divisions. <br>Total = $n + \frac{n}{4} = 600 + \frac{600}{4} = 600 + 150 = 750$.


Discussion 0
Enjoyed this content?
Share your rating and feedback with us. It takes less than a minute!