1. An unknown element $X$ has two naturally occurring isotopes. Isotope $A$ has a mass of $62.93$ u and Isotope $B$ has a mass of $64.93$ u. If the average atomic mass of $X$ is $63.55$ u, what is the percentage abundance of the lighter isotope?
A) $31.0\%$
B) $50.0\%$
C) $69.0\%$
D) $75.5\%$
Correct Answer: C
Solution: Let the abundance of Isotope $A$ ($62.93$ u) be $x$. Then abundance of Isotope $B$ ($64.93$ u) is $(1-x)$. <br> $$63.55 = 62.93(x) + 64.93(1-x)$$ <br> $$63.55 = 62.93x + 64.93 - 64.93x$$ <br> $$63.55 - 64.93 = -2x$$ <br> $$-1.38 = -2x \implies x = 0.69$$ <br> Percentage abundance = $69.0\%$.


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