1. If $x + \frac{1}{x} = 4$, find the value of $x^2 + \frac{1}{x^2}$.
A) 14
B) 16
C) 18
D) 20
Correct Answer: A
<b>Solution:</b><br>
Given $x + \frac{1}{x} = 4$. Square both sides:<br>
$(x + \frac{1}{x})^2 = 4^2$<br>
$x^2 + 2(x)(\frac{1}{x}) + \frac{1}{x^2} = 16$<br>
$x^2 + 2 + \frac{1}{x^2} = 16 \implies x^2 + \frac{1}{x^2} = 16 - 2 = 14$.


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